Digital Electronics Questions

Digital Electronics Questions

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1 Distinguish between digital system and analog system.

Digital System: Uses discrete values (0s and 1s) to represent information. More immune to noise, easier to design, and can be easily stored and transmitted.

Analog System: Uses continuous values to represent information. More prone to noise and distortion, but can represent real-world phenomena more naturally.

2 Describe the process of design.

The design process in digital electronics typically involves:

  1. Problem specification
  2. Formulation of truth tables or state diagrams
  3. Simplification using Karnaugh maps or Boolean algebra
  4. Implementation using logic gates or programmable devices
  5. Testing and verification
3 Write a short note on the following topics:
  • i. Combinational Circuit.
  • ii. Sequential Circuit.

Combinational Circuit: Output depends only on the current inputs. No memory elements. Examples: Adders, multiplexers, decoders.

Sequential Circuit: Output depends on both current inputs and previous states. Contains memory elements (flip-flops). Examples: Counters, registers, memory units.

4 Draw a full adder circuit with truth table, logic diagram, and find the equation of sum and carry.

Truth Table:

ABCinSumCout
00000
00110
01010
01101
10010
10101
11001
11111

Boolean Expressions:

Sum = A'B'Cin + A'BCin' + AB'Cin' + ABCin = A ⊕ B ⊕ Cin

Cout = AB + ACin + BCin

Full Adder Circuit Diagram:

Full Adder Circuit Diagram

Note: In a real implementation, this would show the actual full adder circuit with logic gates.

Implementation:

A full adder can be implemented using two half adders and an OR gate:

  1. First half adder: A ⊕ B (sum), AB (carry)
  2. Second half adder: (A ⊕ B) ⊕ Cin (final sum)
  3. OR gate: AB + (A ⊕ B)Cin (final carry)
5 State Multiplexer. Draw 8x1 multiplexer with truth table.

Multiplexer (MUX): A combinational circuit that selects one of many input lines and directs it to a single output line. Selection is controlled by selection lines.

8x1 Multiplexer:

Has 8 input lines (I0-I7), 3 selection lines (S0-S2), and 1 output line (Y)

Truth Table:

S2S1S0Output Y
000I0
001I1
010I2
011I3
100I4
101I5
110I6
111I7

Boolean Expression:

Y = S2'S1'S0'I0 + S2'S1'S0I1 + S2'S1S0'I2 + S2'S1S0I3 + S2S1'S0'I4 + S2S1'S0I5 + S2S1S0'I6 + S2S1S0I7

6 Construct 4x16 decoder using 3x8 decoder.

A 4x16 decoder has 4 inputs and 16 outputs. It can be constructed using two 3x8 decoders with enable inputs:

  1. Use the higher-order input bit as enable for the two decoders
  2. When higher-order bit is 0, enable the first 3x8 decoder (outputs 0-7)
  3. When higher-order bit is 1, enable the second 3x8 decoder (outputs 8-15)
  4. Connect the lower-order 3 bits to the input of both decoders

This configuration effectively creates a 4x16 decoder from two 3x8 decoders.

7 Implement a full adder circuit with a decoder & two OR gates.

A full adder can be implemented using a 3-to-8 decoder and two OR gates:

From the truth table, we can derive the sum and carry outputs as:

S = A'B'Cin + A'BCin' + AB'Cin' + ABCin

S = m1 + m2 + m4 + m7

S = Σ(1, 2, 4, 7)

Cout = A'BCin + AB'Cin + ABCin' + ABCin

Cout = m3 + m5 + m6 + m7

Cout = Σ(3, 5, 6, 7)

Implementation:

  1. Use the three inputs (A, B, Cin) as inputs to the 3-to-8 decoder
  2. The decoder will generate all 8 minterms (m0 to m7)
  3. Sum output is the OR of minterms 1, 2, 4, and 7
  4. Carry output is the OR of minterms 3, 5, 6, and 7
8 Design clocked JK flip-flop using circuit diagram. Find the characteristic table, truth table, execution table and equation of it.

Clocked JK Flip-Flop:

Constructed using two SR lataches with cross-coupled feedback from output to input.

Characteristic Table:

JKQn+1Operation
00QnNo change
010Reset
101Set
11Qn\'Toggle

Characteristic Equation:

Qn+1 = JQ\' + K\'Q

Excitation Table:

Qn → Qn+1JK
0 → 00X
0 → 11X
1 → 0X1
1 → 1X0
9 Define flip-flop. Design clocked SR flip-flop using circuit diagram. Find the truth table of it.

Flip-flop: A bistable multivibrator that stores one bit of information. It has two stable states and remains in a particular state until triggered to change.

Clocked SR Flip-Flop:

Constructed by adding clock input to basic SR latch using AND gates.

Truth Table:

ClockSRQn+1State
0XXQnNo change
100QnNo change
1010Reset
1101Set
111XInvalid

Note: The S=R=1 condition is forbidden as it leads to unpredictable behavior.